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vroman
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Destructive Interference: Please Help!
Two loudspeakers are 2.36m apart. A person stands 2.8m from one speaker and 3.4m from the other. What is the lowest frequency at which destructive interference will occur at this point?
My answer is wrong, but this is what I did:
3.4m-2.8m=0.6m, so the person is .6m farther from one speaker than the other.
In order to sense destructive Interference, the person, must be one-half wavelength closer to or farther from one speaker than the other, the wavelength must be twice the distance difference. Therefore, Wavelength=0.12m
Using the equation Wavelength =velocity/frequency, I solved for frequency. (velocity of sound is 343 m/s).
My answer: 2858.33Hz
PLease help! Thanks!
Two loudspeakers are 2.36m apart. A person stands 2.8m from one speaker and 3.4m from the other. What is the lowest frequency at which destructive interference will occur at this point?
My answer is wrong, but this is what I did:
3.4m-2.8m=0.6m, so the person is .6m farther from one speaker than the other.
In order to sense destructive Interference, the person, must be one-half wavelength closer to or farther from one speaker than the other, the wavelength must be twice the distance difference. Therefore, Wavelength=0.12m
Using the equation Wavelength =velocity/frequency, I solved for frequency. (velocity of sound is 343 m/s).
My answer: 2858.33Hz
PLease help! Thanks!
