1. Sep 10, 2012 #1

   Debo Industry

   

   A fighter jet has 1 m^2 rcs and is located at 200nmi. Where would a flock of birds with 0.0015 m^2 rcs should be located in order to have the same detectability?

    

   Debo Industry, Sep 10, 2012
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Scarlet macaw DNA points to ancient breeding operation in Southwest
   • • Mathematicians solve age-old spaghetti mystery
   • • New technology can detect hundreds of proteins in a single sample
3. Sep 10, 2012 #2

   jedishrfu

   

   Insights Author

   Staff: Mentor

   isn't this a simple ratio with spherical areas?
   
   1 / ( 4 pi (200)^2 ) = 0.0015 / ( 4 pi x^2 )

    

   jedishrfu, Sep 10, 2012
4. Sep 10, 2012 #3

   Debo Industry

   

   Are you referring to the 4th root equation for radar range ?
   
   ((0.0015/1)^(0,25))*370,4=72,89 km or 32 NMI

    

   Debo Industry, Sep 10, 2012
5. Sep 11, 2012 #4

   jedishrfu

   

   Insights Author

   Staff: Mentor

   I was thinking that the RCS is a % of a larger spherical surface. So the jet has an RCS 1sq meter at 200 nmi. Figure what % is 1 sq meter to the total surface area of the sphere of radius 200nmi (converted to 370636.8 meters).
   
   1 / ( 4 * pi * ( 370636.8 )^2 ) = 5.80e-13 percent
   
   0.0015 / (5.80e-13 % ) =4 * pi * r^2
   
   and r = 45068.86 meters = 24.32 nmi

    

   jedishrfu, Sep 11, 2012
6. Sep 11, 2012 #5

   Debo Industry

   

   Ok , got it . Thank You.

    

   Debo Industry, Sep 11, 2012

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in