Deteriming resonant frequencies

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
mpm
Messages
82
Reaction score
0
I am stumped on how exactly to do this.

I have the function: T(s) = 7/s(s^2+6s+58)

I need to change this to T(iω) and i being a complex root.

This creates: T(iω) = 7/(ωi*(ω^2+6iω+58))

I know I need to plot this function and find out where omega peaks and this will be my resonant frequence.

My only problem is I don't know how to plot this.

I've got a TI-89, Excel, or MATLAB if anyone knows how to do this in either of those.

Please let me know.

Mike
 
Physics news on Phys.org
The circuit will be resonant if there are no real losses. In order for there to be no real losses, the circuit response must be entirely imaginary. Do some algebra to separate the real and imaginary parts, then equivalate the real par to zero. Then try solving it.
 
For some reason, I still can't get anything to come out of what you suggested. I understand what you are saying but its just not working.

Anyone have other comments that might help?

Mike