1. Apr 19, 2006

david2120

using the number obtained 3.407x10^-8 coulombs/mole and the fact that one electron has a charge of 1.60x10^-19 coulombs, calculate how many electrons there are in one mole (i.e. Avogadro's number)

I am not sure but do you do this problem like this?

3.407x10^-8coulombs/mole x 6.022x10^23electrons/mole divide 1.60x10^-19coulombs

2. Apr 19, 2006

Hootenanny

Staff Emeritus
Yep, that looks good to me.

~H

3. Apr 19, 2006

Gokul43201

Staff Emeritus
Please state the entire question - not just a part of it. Where was the number 3.407... obtained from ?

That doesn't look right to me (for one thing, it has units of [mole^-2] which are meaningless), but neither does the question as posted.

4. Apr 19, 2006

dav2008

The huge problem here is that you (improperly) used the number of electrons in a mole to determine...the number of electrons in a mole.

The problem basically boils down to "how many electrons does it take to give a charge of 3.407e-8 C.

Again as it was said above, the first given number is a bit suspicious...

Last edited: Apr 19, 2006
5. Apr 19, 2006

david2120

In Lab I did an experiment in class on trying to determine Faraday's constant and I got 3.407x10^-8 and I have to used that on my calculations

6. Apr 19, 2006

dav2008

Well I hate to break your hopes but you're off by a factor of 1012.

But yes like I said you just want to determine how many electrons it would take to get the charge that you experimentally determined. It's just a simple factor label problem. You are given C/m (Coulombs per mole) and want to determine N/m (number of electrons per mole) given C/N (Charge per electron)

Last edited: Apr 19, 2006
7. Apr 20, 2006

david2120

oh so its 3.407x10^-8 C/m divide 1.60x10^-19coulombs which equals to

2.12938E^11 N/m (number of electrons per mole)