1. The problem statement, all variables and given/known data Charges of 6µC are located at x =0, y = 2.0 m and at x = 0, y = -2.0 m. Charges Q are located at x = 4.0 m, y = 2.0 m and at x = 4.0 m, y = -2.0 m. The electric field at x = 0, y = 0 is (11✕ 103 N/C) i. Determine Q. 2. Relevant equations E=kq/(r3) 3. The attempt at a solution E= kq/(r3)(4m i + 2m j) + kq/(r3)(4m i - 2m j) E= kq/(r3)(8m i) E= kq(8m i)/((x2+y2)3/2) Q= E((x2+y2)3/2)/k(8m) Plug in all values and Q= 13.6 uC The correct answer is -13.6 uC... At what point does the negative sign come in, and why?