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## Homework Statement

Determine ib and ia

Ix = 0.4 mA, R1 = 15k ohm, R2 = 19k ohm, R3 = 23k ohm, R4 = 15k ohm

## Homework Equations

V=IR

## The Attempt at a Solution

I am assuming there are 4 unknown currents in this diagram.

Ix splits into ib and i1.

0.4mA - ib - i1 = 0

i1 - i2 = ia

R2*ib - Vo + R1*(0.4mA - ib) = 0

R3*ia + R4*(0.4mA - ia) = 0

I am confused about the independent current source. In some problems, I have seen it carry a voltage. So if I include a voltage in my analysis for that loop I will have another unknown.

Vx(0.4mA) + R1(0.4mA - ib) + R3(ia) = 0

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