Determine ib and ia
Ix = 0.4 mA, R1 = 15k ohm, R2 = 19k ohm, R3 = 23k ohm, R4 = 15k ohm
The Attempt at a Solution
I am assuming there are 4 unknown currents in this diagram.
Ix splits into ib and i1.
0.4mA - ib - i1 = 0
i1 - i2 = ia
R2*ib - Vo + R1*(0.4mA - ib) = 0
R3*ia + R4*(0.4mA - ia) = 0
I am confused about the independent current source. In some problems, I have seen it carry a voltage. So if I include a voltage in my analysis for that loop I will have another unknown.
Vx(0.4mA) + R1(0.4mA - ib) + R3(ia) = 0