- #1
aisha
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1/(-3y+9) x cannot = 3 is the inverse y=(x+1/9)/(1/-3)? The 1 in the numerator is confusing me also how will I know if the inverse is a function?
t_unit92003 said:first of all, it should be x=1/(-3y+9). Then you solve for y by multiplying both sides by (-3y+9). then divide by x. then subtract 9 from both sides and divide both sides by -3. you should get y=(-3/x)-9.
The inverse of 1/(-3y+9) when x is not equal to 3 is -3y + 9.
X cannot be equal to 3 because it would result in a division by zero, which is undefined.
To determine the inverse of a fraction with a variable in the denominator, you can switch the numerator and denominator and solve for the variable. In this case, the inverse of 1/(-3y+9) is (-3y+9)/1 or -3y+9.
No, the inverse of 1/(-3y+9) cannot be simplified further because there is no common factor that can be factored out.
The domain of the inverse of 1/(-3y+9) is all real numbers except for 3, and the range is also all real numbers except for 0. This is because the original fraction is undefined when x is 3, and the inverse is undefined when the denominator is 0.