1. The problem statement, all variables and given/known data A 17m long ladder is mounted on a fire truck. The ladder itself has mass 130kg , and at the top is a 37kg basket holding a 83kg firefighter. If the ladder makes a 60∘ angle with the horizontal, what's the magnitude of the net torque about the ladder's base? 2. Relevant equations I think center of mass (X1M1+X2M2+X3M3)/(m1+m2+m3) Torue=rFsinθ 3. The attempt at a solution I get a huge number when i try it out. But since is is asking about the ladders base, would it the sine change to cosine? I take the torque from the mass at the end and the torque of the ladder to get the net torque. Kind of stuck.