- #1
mr_coffee
- 1,629
- 1
Hello everyone...
I'm suppose to determine the charge density on either plate. I attached a file which shows the diagram of what I'm talking about. I understand there is no field inside the conducting plate, and the only area penetrated by the field lines is the surface A' projtecting into the space between the plates. I appplied Gauss's law to the left plate...
d = delta.
EoEA = q
EoEA' = dA'
E = d/Eo
I understand up to this point...then they say, Notice that the field between the two plates in this example is exactly twice the field due to a thin sheet of charge. Now I'm lost... why is it exactly twice? Then they say...
E = E1 + E2 = d/[2Eo] + d/[2Eo] = d/Eo;
Why is it d/[2Eo] and not d/Eo ? Also why is there 2 Electrical fields? Thanks.
I'm suppose to determine the charge density on either plate. I attached a file which shows the diagram of what I'm talking about. I understand there is no field inside the conducting plate, and the only area penetrated by the field lines is the surface A' projtecting into the space between the plates. I appplied Gauss's law to the left plate...
d = delta.
EoEA = q
EoEA' = dA'
E = d/Eo
I understand up to this point...then they say, Notice that the field between the two plates in this example is exactly twice the field due to a thin sheet of charge. Now I'm lost... why is it exactly twice? Then they say...
E = E1 + E2 = d/[2Eo] + d/[2Eo] = d/Eo;
Why is it d/[2Eo] and not d/Eo ? Also why is there 2 Electrical fields? Thanks.