Determine the deflection angle of a pellet

  • Thread starter jpnnngtn
  • Start date
  • #1
jpnnngtn
A plastic pellet has a mass of 7.5 X 10^-10 kg and carries a charge of 2.00 X 10^-9 C. The pellet is fired horizontally betweenm a pair of oppositely charged parallel plates. If the electric field strength between the plates is 9.20 X 10^4 N/C and the pellet enters with an initial speed of 150 m/s, determine the deflection angle.

This is the diagram

+ + + + + + + + + + + + + + +

Q+ -------------------------------
\deflection angle(not sccurate drawing)
\
- - - - - - - - - - - ------ - - -
| <-- 2.0cm ----------------->|


*I am almost positive that this problem can be solved by taking the arctan of the change in X over the change in y but i am not sure how to get there. Not in this sense anyway. I can solve these sort of problems when they are not part of electricity.
 
Last edited by a moderator:

Answers and Replies

  • #2
52
0
You know that by entering the electric field, the pellet will experience a force. If I understood the problem correctly the force will be perpendicular to the travel direction of the pellet.

The time spent btw the capacitor can be found; distance/velocity = 2 cm/150

The force can be found since E=F/q

Solve for the force.

F=ma

solve for acceleration

you know the amount of time it has accelerated as well as the value of the acceleration, therefore solve for the distance that the pellet has traveled in the verticle direction.

Now make a triangle. Verticle value being the value above, horizontal value being 2 cm. Find the angle of this triangle and there you go.
 
  • #3
100
0
The pellet follows a parabola, not a straight line so you must get the arctan of vy over vx.
 

Related Threads on Determine the deflection angle of a pellet

Replies
6
Views
546
  • Last Post
Replies
10
Views
2K
  • Last Post
Replies
3
Views
17K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
3
Views
6K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
1
Views
952
  • Last Post
Replies
2
Views
774
  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
4
Views
3K
Top