- #1

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## Main Question or Discussion Point

Determine the integral (x^2) / (2x^3 - 3)^2

This is probably easier than I expect but I have been attempting it using substitution...?

u = (2x^3 -3)

du/dx = 6x^2

dx = du / 6x^2

x^2 / (u^2) . du / 6x^2 - then I lose it because of the canceling out, and I'm unsure what happens to the x's...

I know the answer is -1/6 (2x^3 - 3) + C, but would appreciate the working I miss out. Or if I am attempting it using the wrong methods.

Many thanks,

Ocis

This is probably easier than I expect but I have been attempting it using substitution...?

u = (2x^3 -3)

du/dx = 6x^2

dx = du / 6x^2

x^2 / (u^2) . du / 6x^2 - then I lose it because of the canceling out, and I'm unsure what happens to the x's...

I know the answer is -1/6 (2x^3 - 3) + C, but would appreciate the working I miss out. Or if I am attempting it using the wrong methods.

Many thanks,

Ocis