Please help. How do you solve this
This seems to involve the elliptical integral according to maple...
First, separate out the easy parts; write the integrand as:
(1/e2)e1/(2x) + 4x
Integrate 4x separately, = 2x2
Lookup the integral of e1/(2x) (! I found it on Mathematica, here:
Your result will be (1/e2)[The integral you found...] + 2x2
BTW: Wolfram/Mathematica does find that the answer includes a so-called "Exponential Integral".
Oops I meant exponential not elliptical :)
The bigger question is how to solve an integral exp(ax^q) where q isn't null and isn't 1, I don't think there's a prescription to it.
are you sure it shouldn't be xexp(1/x), cause this can be computed by changing 1/x=u and a series change.
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