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Determine the integral

  1. Jan 18, 2009 #1
    Please help. How do you solve this [​IMG]
     

    Attached Files:

  2. jcsd
  3. Jan 18, 2009 #2
    This seems to involve the elliptical integral according to maple...
     
  4. Jan 18, 2009 #3
    Hi,
    First, separate out the easy parts; write the integrand as:

    (1/e2)e1/(2x) + 4x

    Integrate 4x separately, = 2x2

    Lookup the integral of e1/(2x) (! I found it on Mathematica, here:

    http://integrals.wolfram.com/index.jsp?expr=E%5E%281%2F%282x%29%29&random=false

    !)

    Your result will be (1/e2)[The integral you found...] + 2x2

    BTW: Wolfram/Mathematica does find that the answer includes a so-called "Exponential Integral".
     
  5. Jan 19, 2009 #4
    Oops I meant exponential not elliptical :)
     
  6. Jan 19, 2009 #5
    The bigger question is how to solve an integral exp(ax^q) where q isn't null and isn't 1, I don't think there's a prescription to it.
    are you sure it shouldn't be xexp(1/x), cause this can be computed by changing 1/x=u and a series change.
     
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