Determine the integral

  • Thread starter maobadi
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  • #1
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Please help. How do you solve this
attachment.php?attachmentid=17226&stc=1&d=1232309454.jpg
 

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  • #2
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This seems to involve the elliptical integral according to maple...
 
  • #3
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Hi,
First, separate out the easy parts; write the integrand as:

(1/e2)e1/(2x) + 4x

Integrate 4x separately, = 2x2

Lookup the integral of e1/(2x) (! I found it on Mathematica, here:

http://integrals.wolfram.com/index.jsp?expr=E^(1/(2x))&random=false"

!)

Your result will be (1/e2)[The integral you found...] + 2x2

BTW: Wolfram/Mathematica does find that the answer includes a so-called "Exponential Integral".
 
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  • #4
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Oops I meant exponential not elliptical :)
 
  • #5
MathematicalPhysicist
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The bigger question is how to solve an integral exp(ax^q) where q isn't null and isn't 1, I don't think there's a prescription to it.
are you sure it shouldn't be xexp(1/x), cause this can be computed by changing 1/x=u and a series change.
 

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