- #1

Kdawg

- 34

- 0

I need help with this problem. I know you can figure this out by putting it on a graph and adding the cordinates but I can't find the cordinates of the 60º one. The north one is (20,0) and the west is (-20,0).

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- Thread starter Kdawg
- Start date

- #1

Kdawg

- 34

- 0

I need help with this problem. I know you can figure this out by putting it on a graph and adding the cordinates but I can't find the cordinates of the 60º one. The north one is (20,0) and the west is (-20,0).

- #2

Pyrrhus

Homework Helper

- 2,184

- 1

Are you familiar with vector components?

x = 20cos60

y = 20sin60

(x,y) for the third force.

x = 20cos60

y = 20sin60

(x,y) for the third force.

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