- #1
Frogger Man
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In one model of the hydrogen atom, the electron revolves in a circular orbit around the proton with a speed of 4.6 106 m/s
f = mv^2/r
F is the force of attraction between the electron and proton
m is the mass of the electron
v is the velocity it spins at
r is the radius
(9.11)(1.67*10^-27)K/r^2=[(1.67*10^-27)((4.6*10^6)^2)]/r
when i solve for r, it is not correct, can you tell me if it is setup right
thanks
f = mv^2/r
F is the force of attraction between the electron and proton
m is the mass of the electron
v is the velocity it spins at
r is the radius
(9.11)(1.67*10^-27)K/r^2=[(1.67*10^-27)((4.6*10^6)^2)]/r
when i solve for r, it is not correct, can you tell me if it is setup right
thanks