- #1

- 4

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter sumofmoments=0
- Start date

- #1

- 4

- 0

- #2

Tom Mattson

Staff Emeritus

Science Advisor

Gold Member

- 5,500

- 8

sumofmoments=0 said:i am having problems figuring out how to resolve the moments can someone help me please

OK, I need to see what you've done on this (that's our policy). It's not a difficult problem, so don't be afraid of it. Take the following steps:

1. Calculate the moments due to the loads shown. The standard convention is that counterclockwise moments are in the positive direction, and that clockwise moments are in the negative direction.

So think

2. Determine the reactions with Newton's laws. Sum the forces in the y-direction, and sum the moments in the z-direction. Include unknown reaction forces, and set the sums equal to zero. Then solve for the unknowns.

- #3

- 90

- 1

If a force is acting upwards or downwards from the point at which you are resolving, it is the horizontal (do not include vertical) distance to the force (so the point to measure to would be exactly above or below the force). multiplied by the force.

Similarly, if a force is acting horizontally from the point at which you are resolving it is the vertical distance multiplied by the force magnitude.

If the force is acting at an angle you can resolve everything into x and y components, to make it much easier to calculate.

For example: For a 10N force acting at 23 degrees, the horizontal force is 10cos23, while the vertical force is 10sin23. From my memory though this doesn't seem to be a problem in your question.

-For the reaction at B you don't need moments, the forces acting vertically are in balance. From this you can calculate B.

-For the reaction at A, perhaps it would make it simpler for you to understand if you removed 'A' and replaced it with a horizontal force (the reaction force at A) which you can then calculate. Also, add in the calculated force at B.

-Then choose a convenient position to resolve moments at. Somewhere where the force at A is not cancelled out perhaps?

Then take moments,

Clockwise = anticlockwise.

Have a go =).

Similarly, if a force is acting horizontally from the point at which you are resolving it is the vertical distance multiplied by the force magnitude.

If the force is acting at an angle you can resolve everything into x and y components, to make it much easier to calculate.

For example: For a 10N force acting at 23 degrees, the horizontal force is 10cos23, while the vertical force is 10sin23. From my memory though this doesn't seem to be a problem in your question.

-For the reaction at B you don't need moments, the forces acting vertically are in balance. From this you can calculate B.

-For the reaction at A, perhaps it would make it simpler for you to understand if you removed 'A' and replaced it with a horizontal force (the reaction force at A) which you can then calculate. Also, add in the calculated force at B.

-Then choose a convenient position to resolve moments at. Somewhere where the force at A is not cancelled out perhaps?

Then take moments,

Clockwise = anticlockwise.

Have a go =).

Last edited:

Share:

- Replies
- 6

- Views
- 3K