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**1. Determine the voltage v as labeled in Fig. 3.72, and calculate the power supplied by each current source.**

## Homework Equations

KVL and Ohms Law

## The Attempt at a Solution

The first step is to try and simplify the circuit so that it gives a resistance of 0.75Ω, which is obtained by combining the two resistors that are in parallel: [itex]\frac{1}{1 + \frac{1}{3}} [/itex]. We thus now have a current dependent current source, 3i

_{x}, a current source of 2A and a resistor of 0.75Ω, with the total current flowing counterclock-wise.

Using this, KCL can be applied:

-3ix - 2 = 0 so that ix = -2/3

V is then:

(1)(-2/3) + (1)(-3)(-2/3) + (-2)(3) = -14/3

The power supplied by each current source then should be:

P(3ix) = (14/3)(2/3) = 28/9

P(2A) = (14/3)(-2) = -28/9

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