Determing wavelength of sound wave from steel string

[LBRRIT2390]

Homework Statement

A 120 cm-long steel string with a linear density of 1.2 g/m is under 100 N tension. It is plucked and vibrates at its fundamental frequency.

What is the wavelength of the sound wave that reaches your ear in a 20 $$\circ$$C room?

Homework Equations

Fundamental Frequency

f₁ = $$\frac{v}{2L}$$

Fundamental Frequency of a stretched string

f₁ = $$\frac{1}{2L}$$$$\sqrt{\frac{T_s}{\mu}}$$

Wavelengths of standing wave modes

$$\lambda$$_m = $$\frac{2L}{m}$$

$$\lambda$$_m = $$\frac{v}{f_m}$$

The Attempt at a Solution

I solved fundamental frequency as 143.3 then used

$$\lambda$$_m = $$\frac{v}{f_m}$$ to find the wavelength.

I also tried solving for fundamental frequency using

f₁ = $$\frac{1}{2L}$$$$\sqrt{\frac{T_s}{\mu}}$$

All of my answers have been incorrect. Please help!

 

[LBRRIT2390]

Speed of wave in string: v = $$\sqrt{\frac{T_s}{\mu}}$$

T_s = 100N​

$$\mu$$ = 0.0012kg/m​

v = 288.7​

Fundamental Frequency: F₀ = $$\frac{v}{\lambda_0}$$

$$\lambda$$₀ = 2L = 2*1.2​

$$\lambda$$₀ = 2.4​

f₀ = $$\frac{\sqrt{\frac{T_s}{\mu}}}{2L}$$

In the air:

$$\lambda$$ = $$\frac{v}{f_0}$$

$$\lambda$$ = $$\frac{v}{\frac{\sqrt{\frac{T_s}{\mu}}}{2L}}$$

$$\lambda$$ = $$\frac{v2L}{\frac{\sqrt{T_s}}{\mu}}$$

$$\lambda$$ = $$\frac{344m/s * 2.4}{288.7}$$ = 2.86