Determining Cache Size: Find Data Size

[bl4ke360]

Homework Statement

Homework Equations

total cache size = (2^(index bits)) * [(associativity)(tag bits + valid bits + data size)]
(Correct me if this is wrong)

The Attempt at a Solution

I came up with 2^11 cache sets, therefore it's 8-way associative because 2^14 / 2^3 = 2^11. And 8=2^3.
Therefore 8 comparators, 10 bits each because the tag is 10 bits.
I'm stuck on the last part where it asks to determine the size of the cache because I'm not sure what the data size is. From what I have so far the equation would be:
2^11 * (8(10+(1+1+1+1)+data size))

If this is correct, can someone tell me how the data size is determined so that I can solve that equation?

 

[KataKoniK]

Hi there! Your equations and calculations look correct so far. The data size is typically determined by the size of each cache block or line. This refers to the amount of data that can be stored in each individual cache entry. For example, if each cache block can hold 32 bytes of data, then the data size in your equation would be 32. This number can vary depending on the processor architecture and design decisions.

To determine the size of the cache, you can use the following equation:

Total cache size = (2^(index bits)) * [(associativity)(tag bits + valid bits + data size)]

In this equation, you already have the index bits and associativity calculated. The tag bits and valid bits are determined by the size of the address and the number of bits used for indexing and tag storage. The data size, as mentioned before, is determined by the size of each cache block.

Hope this helps! Let me know if you have any further questions. Good luck with your calculations!