Please take a look at the attached picture. How would you go about finding the charge on capacitor 2? My method which didnt work: -combine capacitors 2,3,4 and 5 and get the equivalent capacitance Ceq -Since V across C1 is equal to V across Ceq we can find charge on Ceq by V/Ceq -Then voltage on Ceq is equal to voltage on C5 and C234(combination of capacitors 2,3 and 4. -Then use that voltage to find charge of 2,3,4 combined. Then voltage on 2 and 3 is equal to voltage on 4 since they are 'in parallel' and find this voltage by doing charge on 2,3,4 divided by C234 -Then charge on 2 and 3 can be found by V23*C23=q23=q2(series) I am thankful for any help.