- #1
euphtone06
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Homework Statement
Cylin. surfaces [tex]\rho[/tex] = 1 , 2 , 3, cm have uniform surface charge density of 20, -8, 5 nC/m^2.
What is the total electric flux that passes through the closed surface [tex]rho[/tex] = 4 cm and z(from 0 to 1 m)?
And what is [tex]\vec{D}[/tex] at the point [tex]\rho[/tex]= 4 cm , [tex]\phi[/tex]= 0 , z = .5 cm
Homework Equations
[tex]\Phi[/tex]= E2piRL=[tex]\lambda[/tex]L/8.85x10-12
E = [tex]\rho[/tex]/(2pi8.85x10^-12 [tex]\rho[/tex])
The Attempt at a Solution
So the closed surface from which to determine the flux is at [tex]\rho[/tex] = .04 m
I frankly am unsure how to use the equations to get the total flux.
[tex]\Phi[/tex]1 = 20(.01)/8.85x10^-12
[tex]\Phi[/tex]2= -8(.02)/8.85x10^-12
[tex]\Phi[/tex]3= 5(.03)/8.85x10^-12
Is it as simple as adding them all up? Or does the center most cylindrical surface at 1 cm have an affect on 2 cm surface which then in turn affects the 3 cm? I have a feeling this is completely wrong so I attempted it a different way
[tex]\int[/tex].04*20
[tex]\int[/tex].04*-8
[tex]\int[/tex].04*5
total flux = sum of the integrals?
I obviously am struggling with this concept any help would be appreciated Thanks!