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confusedbyphysics
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K(a) for HX is 7.5 x 10^-12. What is the pH of a 0.15-M aqueous solution of NaX?
a. 7.87
b. 1.85
c. 5.97
d. 8.03
e. 12.15
HX --> H+ + X-
I found H+ concentration, which is 1.06 X 10-6, then found pH of this, and it is 5.97. I wasn't sure where to go from here so I guessed 5.97 and it is wrong (I get another guess).
How do I go from finding the pH of the HX to finding the pH of the NaX? 14 - 5.97 - 8.03 which is an answer, but I'm not sure why I'd do this? isn't the conjugate base just the X-? Thanks for any help
a. 7.87
b. 1.85
c. 5.97
d. 8.03
e. 12.15
HX --> H+ + X-
I found H+ concentration, which is 1.06 X 10-6, then found pH of this, and it is 5.97. I wasn't sure where to go from here so I guessed 5.97 and it is wrong (I get another guess).
How do I go from finding the pH of the HX to finding the pH of the NaX? 14 - 5.97 - 8.03 which is an answer, but I'm not sure why I'd do this? isn't the conjugate base just the X-? Thanks for any help
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