K(a) for HX is 7.5 x 10^-12. What is the pH of a 0.15-M aqueous solution of NaX?(adsbygoogle = window.adsbygoogle || []).push({});

a. 7.87

b. 1.85

c. 5.97

d. 8.03

e. 12.15

HX --> H+ + X-

I found H+ concentration, which is 1.06 X 10-6, then found pH of this, and it is 5.97. I wasn't sure where to go from here so I guessed 5.97 and it is wrong (I get another guess).

How do I go from finding the pH of the HX to finding the pH of the NaX? 14 - 5.97 - 8.03 which is an answer, but I'm not sure why I'd do this? isnt the conjugate base just the X-? Thanks for any help

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# Homework Help: Determining pH problem, help please

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