- #1

Liesl

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## Homework Statement

In a binomial experiment with number of trials n=1, the probability of success p represents a proportion. The ratio of successes X to the n can be used as an estimator of the proportion. For large n the number of successes in a binomial experiment is normally distributed, so that:

z=(X-np)/√(npq)

has zero mean and unit variance. Use the above information to determine the density for the estimate of the proportion ρ=X/n.

## Homework Equations

Density function for normal distribution: f(x)=1/(σ√(2∏))*e^-((x-μ)^2/(2σ^2)) where μ=mean and σ=standard deviation

When constructing a random variable z with zero mean and unit variance:

z=(X-μ)/σ

## The Attempt at a Solution

Can I simply plug in μ=np and σ=√(npq) into my equation for a normal distribution? μ and σ are for the sample space, do I need to change tactics for the estimate of the proportion? Thanks, any help/guidance is appreciated.