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b) How much torque is required to stop it in 7.0 s?

1500 rpm * 2pi rad = 9424.78 rad/m

(9424.78 rad/m) /60 s = 157.08 rad/s

I = 1/2mr2

I = 1/2(2.8 kg)(.18 m)2 = 0.04536 kgm2

L = Iw = (0.04536 kgm2)(157.08 rad/s) = 7.13 kgm2/s

I have determined the angular momentum, but I am unsure of how to determine the torque required to stop it in 7 s

How do you determine this with the torque formula and time involved? Any help?