# Determining voltage of a node?

1. Sep 19, 2010

### Chandasouk

http://img.photobucket.com/albums/v405/RagingCamel/viewer.png

I'm trying to answer the steps on this hw but have no idea what i am doing.

For the first step, at node e the KCL equation would just be ix+0.5ix=0?

Since ix and 0.5ix are both entering the node of e?

Also, where are the + and - signs placed on the resistors?
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Sep 19, 2010

### klondike

No, this is not right. Sum of currents entering a node = Sum of currents leaving a node. 1.5ix=current passing the 10ohm resistor which is not zero.

3. Sep 19, 2010

### Chandasouk

How do I find what is entering/leaving node e?

From node c i see current i_x goes through 2 ohms, reaches node d and splits into two paths, one heading towards node b and the other across resistor 3 ohms. So, the current through 3 ohms is entering node e?

I'm pretty lost as to what to do