about deterministic systems and disproving the schrodinger's cat theory.(adsbygoogle = window.adsbygoogle || []).push({});

if your system state is determined by a quantum wave function then the theory states that your wave function collapses as soon as it is observed... if you set up your system so that after a set time period based on the state of the system, the system say releases a particle or doesn't release a particle. the act of the particle being observed will collapse the system, but the trick is if the system doesn't release a particle then according the theory the system will still be in a quantum super position (and half of the time it will have released a particle) and it will there for either defy causality or have collapsed by some other means.

Is this correct logic, or am I missing something?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Deterministic systems and disproving the schrodinger's cat theory

Loading...

Similar Threads for Deterministic systems disproving |
---|

A Information of system vs system, apparatus and environment |

B Is quantum physics "retro-deterministic"? |

B Non-deterministic Hidden variables that can't be described by math |

B Wave function deterministic yet not classical |

B Examples of systems that evolve deterministically |

**Physics Forums | Science Articles, Homework Help, Discussion**