# Diagonalisable matrix

1. Sep 19, 2009

### sassie

1. The problem statement, all variables and given/known data

Is the following matrix diagonalisable?

[0 0 0 0 0 ....0
0 1 0 0 0 ....0
0 0 2 0 0 .... 0
0 0 0 3 0 ....0
. . .
. . .
. . .
. .0
0 0 0 0 0 0....n]

(having trouble showing the mtarix, basically 0,1,2,3...n down the diagonal and zeroes off-diagonal)

2. Relevant equations

Given.

3. The attempt at a solution

I thought that because it contains the zero vector, the matrix doesn't have n linearly independent columns, thus not diagonalisable? I'm not entirely sure. Plus, is it possible to find the eigenvalues and eigenvectors for the matrix?

2. Sep 19, 2009

### gabbagabbahey

If you mean

$$\begin{pmatrix}0&0&0&0&\ldots&0\\0&1&0&0&\ldots&0\\0&0&2&0&\ldots&0\\0&0&0&3&\ldots&0\\\vdots&\vdots&\vdots&\vdots&\ldots&\vdots\\0&0&0&0&\ldots&n\end{pmatrix}$$

then isn't the matrix already diagonalized?

3. Sep 19, 2009

### sassie

Yes, that's the matrix that I mean. :)

So, if the matrix has a zero column, it can still be diagonalisable?
I thought that if it didn't have n linearly independent vectors, it cannot diagonalisable...

4. Sep 19, 2009

### gabbagabbahey

Obviously, since your matrix is diagonal, choosing $P=I_n$ (the $n\times n$ identity matrix) will show that it is diagonalizable.

I think you are mistaking a matrix's columns for its eigenvectors; if an $n\times n$ matrix doesn't have $n$ linearly independent eigenvectors it isn't diagonalizable.

Last edited by a moderator: May 4, 2017
5. Sep 19, 2009

### sassie

Okay, thank you! I should obviously read my notes better next time! :)

You've been a great help!