The molecular bond between the carbon and oxygen atoms in the diatomic carbon monoxide molecule can be treated as a spring with elastic constant k. The carbon atom has a mass of 12 amu and the oxygen atom has a mass of 16 amu, and the average separation of the two nuclei in the carbon monoxide molecule is 1.4x10^-10m.
A carbon monoxide molecule makes a transition from the first excited rotational state to the ground state. What is the wavelength of the emitted radiation?
E = l(l+1)h_bar^2 / 2I
E = energy
l = quantum number
h_bar = plancks constant / 2*pi
I = moment of inertia
E = hc/lambda
h = placks constant
c = speed of light in vacuum
lambda = wavelength
The Attempt at a Solution
I calculated the moment of inertia I in a previous part of the question and it is correct.
I = 2.23 x 10^-46 kgm^2
I assumed that ground state means that l=0 and first excited state means that l=1. I calculated the energy difference between these two states. Then calculated the debroglie wavelength. But I didn't get the correct answer.
Correct answer should be : 2.6 mm