# Did I do something wrong?

The problem is -

Consider the following accept constants:

Radius of the moon = 1.74 x 10^6 m
Average moon-earth distance = 3.84 x 10^8 m

a) What is the apparent angle the diameter of the moon subtends, as seen from the earth? Answer in units of degrees.

I doubled the radius of the moon to get the diameter, and then divided the result by the moon-earth distance. Then, I took the inverse tangent of the result.

I get 51.92 degrees. My college website is telling me this is wrong. Do you get a different answer?

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Astronuc
Staff Emeritus
tan(51.92°) = 1.276, so it would appear there is an error in the computation.

The ratio of 2*Lunar Diameter to Earth-Moon distance is ~0.009, so the tan-1 should be small - less than 1°.

David
onetroubledguy said:
Then, I took the inverse tangent of the result. I get 51.92 degrees. My college website is telling me this is wrong.
Did you check that your calculator was set to the appropriate degrees/radians setting?

quasar987
Homework Helper
Gold Member
Why did you doubled the lunar radius before taking the inverse tangeant? The tan thing works on rectangle-triangles only. I say find the angle subtented by half of the moon, and then multiply that angle by 2 to get the total angle subtented by the diameter.

quasar987 said:
Why did you doubled the lunar radius before taking the inverse tangeant? The tan thing works on rectangle-triangles only. I say find the angle subtented by half of the moon, and then multiply that angle by 2 to get the total angle subtented by the diameter.
Wouldn't you get the same answer?

Well, the angle subtended by half the moon is 25.96. So 25.96*2 = 51.92

quasar987
Homework Helper
Gold Member
I get 0.2596; 100 times less.

quasar987 said:
I get 0.2596; 100 times less.
I thought 0.2596 needs to be converted into a percent? Is that the only mistake I made? Yeah I'm an idiot. Now that I actually picture how insane of a degree 51.92 would be, it's clear as day. Thanks for the help!

Last edited:
cks
Even you have made a mistake by changing it into percentage, but I don't understand why you have to double the radius of the moon. Isn't it