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[tex] 4x^2 - 9y^2 + 32x + 18y + 91 = 0 [/tex]

[tex] 4x^2 + 32x [/tex]..................[tex]-9y^2 + 18y[/tex]..................[tex]+91 = 0[/tex]

[tex] 4(x^2 + 8x + 16) [/tex]..........[tex]-9(y^2 - 2y + 1)[/tex]..........[tex]+91 -16 -1 = 0[/tex]

[tex] 4(x + 4)^2 [/tex]..................[tex]-9(y - 1)^2[/tex]..................[tex]+74 = 0[/tex]

therefore

[tex]\frac{(y - 1)^2}{4} - \frac{(x+4)^2}{9} = 74[/tex]

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# Homework Help: Did I do this coversion to Standard correctly?

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