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[tex]\int \frac {e^x+4}{e^x}dx =?[/tex]
Here's what I did:
[tex]\int \frac {e^x+4}{e^x}dx = \int e^{-x}(e^x+4)dx [/tex]
[tex]\int e^{-x}(e^x+4)dx =\int 1+4e^{-x} = x-\frac {4e^{-x+1}}{x+1}[/tex]
Did I do this correctly? Is there a more simplified answer?
Here's what I did:
[tex]\int \frac {e^x+4}{e^x}dx = \int e^{-x}(e^x+4)dx [/tex]
[tex]\int e^{-x}(e^x+4)dx =\int 1+4e^{-x} = x-\frac {4e^{-x+1}}{x+1}[/tex]
Did I do this correctly? Is there a more simplified answer?