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Did I put this truth table in the k-map correctly?

  1. Oct 7, 2005 #1
  2. jcsd
  3. Oct 7, 2005 #2
    no, you have an error. you have two c' entries on thr map but only one in the original truth table.
     
  4. Oct 7, 2005 #3
    so the 1's should be here:
    011
    101
    111
    110
    right?>
     
  5. Oct 12, 2005 #4

    ranger

    User Avatar
    Gold Member

    You could simplify using boolean theorems to check your answer.

    z= A'BC+AB'C+ABC'+ABC

    The last term ABC, has at least two variables common in the other terms.

    Z = A'BC+ABC+AB'C+ABC+ABC'+ABC
    Z = BC(A'+A) + AC(B'+B) + AB(C'+C)
    Z = BC + AC + AB

    You have BC + AC' + AB


    The mistake that you made in the K-map is that you have AB'C' instead of AB'C.
     
    Last edited: Oct 12, 2005
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