# Did I solve this right?

1. Jan 19, 2009

### ektrules

Here's the equation.
$$\frac{mv^{2}}{r}=\frac{mg+C_{a}v^{2}cos\vartheta}{cos\vartheta-\mu sin\vartheta}\left(\mu cos\vartheta+sin\theta\right)-C_{a}v^{2}sin\vartheta$$
After trying to solve for v, I got this:
$$v=\sqrt{\frac{mg\mu cos\vartheta+mg sin\vartheta}{-2\mu C_{a}cos\vartheta-2\mu C_{a}sin\vartheta+\frac{mcos\vartheta-\mu msin\vartheta}{r}}}$$
I'm not sure if this is correct though. I never took trig, so all the sin's and cos's confuse me, and I'm not exactly sure how to perform algebra on them.

2. Jan 19, 2009

### mathman

I haven't checked your result. However, solving for v doesn't require knowing trig. Just put all the v2 on one side of the equation, and put all the other terms on the other side. Then divide by the coefficent of v2 and take the square root.