# Did i solved this limit correctly

1. Feb 11, 2009

### transgalactic

$$lim_{x->\infty}\frac{3x-cosx}{4x+sinx}=lim_{x->\infty}\frac{\frac{3x-cosx}{x}}{\frac{4x+sinx}{x}}=lim_{x->\infty}\frac{3-0}{4-0}=0.75$$

i thought bounded/infinity=0

??

2. Feb 12, 2009

### Staff: Mentor

You have the correct limit, but you should remove the limit operator from the expression below, since you have already "passed to the limit" in the previous expression:
$$lim_{x->\infty}\frac{3-0}{4-0}=0.75$$

3. Feb 12, 2009

thanks