[tex](adsbygoogle = window.adsbygoogle || []).push({});

lim_{x->\infty}\frac{3x-cosx}{4x+sinx}=lim_{x->\infty}\frac{\frac{3x-cosx}{x}}{\frac{4x+sinx}{x}}=lim_{x->\infty}\frac{3-0}{4-0}=0.75

[/tex]

i thought bounded/infinity=0

??

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# Homework Help: Did i solved this limit correctly

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