- #1

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lim_{x->\infty}\frac{3x-cosx}{4x+sinx}=lim_{x->\infty}\frac{\frac{3x-cosx}{x}}{\frac{4x+sinx}{x}}=lim_{x->\infty}\frac{3-0}{4-0}=0.75

[/tex]

i thought bounded/infinity=0

??

- Thread starter transgalactic
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- #1

- 1,395

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lim_{x->\infty}\frac{3x-cosx}{4x+sinx}=lim_{x->\infty}\frac{\frac{3x-cosx}{x}}{\frac{4x+sinx}{x}}=lim_{x->\infty}\frac{3-0}{4-0}=0.75

[/tex]

i thought bounded/infinity=0

??

- #2

Mark44

Mentor

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[tex]lim_{x->\infty}\frac{3-0}{4-0}=0.75 [/tex]

- #3

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thanks

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