Diesel Emission Rate Caculation (soot amount)

[Su Solberg]

Hey every one.
I have problem in caculating the soot content in (gram of soot)/(1 liter of exhaust gas).

Euor 4 emission standard of PM emission for HD diesel Engine is 0.02 g/kwh (from wikipedia)

So, If I have an engine rated 200kw, the PM is also 0.02g/kwh, Exhaust flow is 1000CFM
then the soot content in the exhaust flow is (in g/liter):

The amount of soot generated in one hour:
0.02g/kwh * 200kw
=4 g/ hour
=0.0666 g/ min

1000CFM = 28316.8 liter/min

so the PM emission rate is:
(0.0666g/min) / (28316.8liter/min)
= 0.0023mg/ Liter
------------------------------------------------------------
Is the above caculation correct??
Thanks for your help in advance.

 

[Achy47]

Hello there,

Thank you for reaching out with your question. Your calculation seems to be correct based on the information provided. However, it is important to note that the emission standard for PM is specified as grams per kilowatt-hour (g/kwh), while the exhaust flow is measured in cubic feet per minute (CFM). In order to accurately calculate the soot content in grams per liter, you will need to convert the exhaust flow from CFM to liters per minute (L/min) and then multiply it by the PM emission rate. The conversion factor for CFM to L/min is 28.3168, so the calculation would be:

(0.0666 g/min) / (1000 CFM * 28.3168 L/min per CFM) = 0.0023 mg/L

I hope this helps clarify any confusion and you are able to accurately calculate the soot content in your exhaust gas. Let me know if you have any further questions.