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Diff Eq Problem

  1. Jun 20, 2009 #1
    1. Give the general solution for the following problem

    2. y'=1+x^2+y^2+x^2y^2

    3. I have attempted to separate the equation and came up with the following:
    y'=1+y^2+x^2(1+y^2) from there I ended up with (y'-y^2-1)/(1+y^2)=x^2
    I am stuck on what step to take next. I am sure I am just missing something simple.
     
    Last edited: Jun 20, 2009
  2. jcsd
  3. Jun 20, 2009 #2
    So you want to get y'=q(y)*p(x) from your original equation. How can you do that?
     
  4. Jun 20, 2009 #3
    Thanks, i got it, i knew i was forgetting something small, it factors out to (x^2+1)(y^2+1) Makes the whole thing a lot easier.

    Thanks again for the help.
     
  5. Jun 21, 2009 #4
    What is general solution?
     
  6. Jun 21, 2009 #5
    The general solution I came up with is y=tan(x3/3+x+C)
     
    Last edited: Jun 21, 2009
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