Diff Eq Problem

  • Thread starter jrodss
  • Start date
  • #1
5
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1. Give the general solution for the following problem

2. y'=1+x^2+y^2+x^2y^2

3. I have attempted to separate the equation and came up with the following:
y'=1+y^2+x^2(1+y^2) from there I ended up with (y'-y^2-1)/(1+y^2)=x^2
I am stuck on what step to take next. I am sure I am just missing something simple.
 
Last edited:

Answers and Replies

  • #2
66
0
So you want to get y'=q(y)*p(x) from your original equation. How can you do that?
 
  • #3
5
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Thanks, i got it, i knew i was forgetting something small, it factors out to (x^2+1)(y^2+1) Makes the whole thing a lot easier.

Thanks again for the help.
 
  • #4
365
0
What is general solution?
 
  • #5
5
0
The general solution I came up with is y=tan(x3/3+x+C)
 
Last edited:

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