I need help figuring out the solution to this diff.eq.(adsbygoogle = window.adsbygoogle || []).push({});

y(x) = x + (1/2)*∫(from u=-1 to 1)[ ( 1-| x – u | ) y(u) du] , x є [ -1, 1]

I have to show that:

y``(x) + y(x) = 0 , x є [ -1, 1]

subject to:

y(1) + y(-1) = 0

y`(1) + y`(-1) = 2

Thanks for any help you can give.

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# Diff.eqn. help

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