(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

(3x-2y+1)dx+(3x-2y+3)dy=0

this a piece of my solution: (pls correct if i'm wrong)

I thought of solving it using miscellaneous substitution using (3x-2y+1) as u...

du= 3dx- 2dy ,dx=(du+2dy)/3 so,

>u[(du+2dy)/3) + udy +2dy =0

>u(du +2dy) + 3udy + 6dy =0

>udu +(5u+6)dy=0

>[u/ (5u+6)] du + dy =0

integrating it:

> (5u+6)/25 + 6/25 [ln (5u+6)] + y = 0

>(5u+6) + 6[ln(5u+6) + 25y =0

>(15x-10y+11) + 6[ln(15x-10y+11)] +25y =0

but this answer is way too different from the answer on the book the answer there is:

5(x+y+c) = 2ln[15x-10y+11] ... what could be my mistake?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Diff. equation help

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