Note: I think I get too specific about the problem when what I am asking about a specific part of the whole problem.(adsbygoogle = window.adsbygoogle || []).push({});

The problem: Find a shape with volume V(t) and surface area Ab(t) such that Pe(t) = Pa(t).

In the interest of time I will not refer to what all variables signify; I will keep it mathematic unless you request something explained.

Im fairly certain I know how to go about solving most of what I am about to present but I would like some advice where noted.

To simplify Im going to define: dPo/dt =Po, dV/dt =V, dr/dt =r

Basically a bolded variable to signify any derivative with respect to time. I may not explicitly state that for other introduced variables so please note that.

Also constants will be presented as a lowercase in []; i.e., [a], [x].... Variables will be regular text and assumed variable with time unless otherwise noted: so Ab(t) = Ab. Also note that if two variables are side by side I will separate them by an operator to avoid Po(t) = Po being misconstrued as P*o.

Basically what I am trying to do is equate the two eventual sides of an equation making up Pe(t) = Pa(t).

For Pe(t) and the lefthandside(LHS) the governing equations are as follows:

1)V=rAb

2)r= [a]Po^[n]

3)Po+*(1/V)*Po - [c]*([d]-[e]Po)*(Ab/V)*Po^[n] = 0

We know the value ofr(0) and 2) is just an empirical relation betweenrand Po.

Now ignore the right-hand-side of the equality and say that we already know this; Pa(t) is a known function.

For the LHS first we get Po and then Pe.

Pe is related to Po by: Pe = Po/[m]

My question is specific to solving for Po by finding a shape; namely we need to find two unknowns (Ab(t) and V(t)) that constitute one shape (out of an infinite number of possibilities) that can satisfy the equality.

Now when I do this I use Eulers method to "discretize" Po.We know Po(0)

The problem is incomplete with whats currently given because the variables with which we ultimately need are Ab and V? This whole problem is basically finding a shape (a shape per every interval of time that is; so it is a shape changing with time) that satisfies Pe = Pa.THIS IS WHERE IM LOOKING FOR SOME ADVICE.How can you resolve this incompletion in the most general sense? For example I know you can simply assume a cylinder and use:

4) Ab = 2*pi*r'*h

5) V = pi*(r'^2)*h

(the derivative of r wrt to time in the edits is not the bolded r just dr/dt)

We can get r' via dr/dt and knowing r'(0)... the r' here is radius while the r in dr/dt is referring to the distance at which the shape surface diminishes. Think of dr/dt as the rate at which the surface of the shape diminishes perpendicular to Ab so in the case of a cylinder (neglecting the ends of the cylinder) the radius r' at some time = the current radius - the current dr/dt*(time step).

These two satisfy 1)., taking the derivative wrt time of 5) and plugging into 4) gives 1). The initial values, Ab(0) and V(0) must satisfy 3).

I think Im walking around the answer to my question in what I just wrote however. I think 1) is the general sense and any equations such as 4) and 5) satisfying 1) are compatible.

Basically, I wanted to keep the solution general.

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# Diff Equation Problem Help

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