# Diff Equation

1. Jun 21, 2009

### mamma_mia66

1. The problem statement, all variables and given/known data
y2dx -x(2x+3y)dy =0 I have to recognize the equation and solve it

2. Relevant equations

3. The attempt at a solution

I did y2dx - (2x2+ 3yx) dy=0
which is a homogeneous now
after I substitude x=uy
dx=udy + ydu

I stuck here after the substitution

y2udy+y3du - 2x2dy + 3yxdy=0

please someone help if I am not in right direction from the begining.

2. Jun 21, 2009

### HallsofIvy

I am more accustomed to write y= ux but your method is equivalent.
Saying x= uy is the same as saying u= y/x. Divide your last equation by $x^2$ and see what you get!

3. Jun 21, 2009

ok, thanks.