Covariance of Differential Operators in Special Relativity

In summary, Chapter 2 of Ziebach's new book A First Course in String Theory discusses the transformation of objects under boosts along the x^1 axis in relation to special relativity. Part (b) of Problem 2.3 asks for a demonstration that the differential operators are covariant. The inverse of the contravariant metric tensor is used to produce lower index objects, resulting in a change of sign for the time component. The chain rule is then used to show that the partial derivatives are constant in this case.
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I am doing the excercises on Chapter 2 of Ziebach's new book A First Course in String Theory. Part (b) of Problem 2.3 asks us to show that the objects [tex]\partial/{\partial x^{\mu}} [/tex] transform under a boost along the [tex]x^1[/tex] axis in the same way as the [tex]a_{\mu}[/tex] do.

In other words, to show the differential operators are covariant in special relativity. I haven't done this demonstration before and all the tricks I have come up with don't seem to get there. Can anyone help?

His "lower index objects" are produced from upper index objects by multiplying with the inverse of the contravariant metric tensor : [tex] a_{\mu} = \eta_{\mu\nu} a^{\nu} [/tex]. This has the effect of changing the sign of the 0 (time) component of the vector. Signature is -+++.
 
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For any transformation of coordinates, let [tex]x^{mu}[/tex] be the old coordinates and [tex]x^{mu}'[/tex] the new coordinates. Use the chain rule:
[tex]\frac{\partial }{\partial x^{mu}'}= \frac{\partial x^{mu}}{\partial x^{mu}'}\frac{\partial }{\partial x^{mu}}[/tex].
 
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  • #3
Hah! Thanks! I missed that because in this case
[tex]\frac{\partial{x^{\mu}}}{\partial{x'^{\mu}}} [/tex]
is constant, being a particular Lorentz trannsform.

Thanks again Halls.
 

1. What does it mean for a "diff operator to be covariant"?

When we say that a diff operator is covariant, it means that it transforms in the same way as the coordinates under a change of coordinates. In other words, if we change the coordinates of our system, the diff operator will also change accordingly.

2. What is the significance of a diff operator being covariant?

The significance of a diff operator being covariant lies in its ability to maintain its form and function under a change of coordinates. This makes it a powerful tool in mathematical and scientific fields where coordinate transformations are common, such as in general relativity and differential geometry.

3. How is the covariance of a diff operator different from its contravariance?

While a covariant diff operator transforms in the same way as the coordinates, a contravariant diff operator transforms in the opposite way. This means that as the coordinates change, the contravariant diff operator will change in the opposite direction. In other words, they have different transformation rules under coordinate changes.

4. Are all diff operators covariant?

No, not all diff operators are covariant. Some diff operators, such as the gradient operator, are actually contravariant. It depends on the specific properties and characteristics of the diff operator and the system in which it is being used.

5. What are some applications of covariant diff operators?

Covariant diff operators have numerous applications in various fields of science and mathematics. They are commonly used in general relativity, differential geometry, and other areas of physics and engineering. They can also be applied in the study of curved spaces, differential equations, and vector calculus, among others.

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