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pleaseeeee help .

Thankyou sooo much :)

- Thread starter Anoushka
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- #1

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pleaseeeee help .

Thankyou sooo much :)

- #2

collinsmark

Homework Helper

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Hello Anoushka,

Welcome to Physics Forums!

I can't give you the answer, but I will give you a couple things to consider.

pleaseeeee help .

Thankyou sooo much :)

//=============

// Consideration 1

//=============

It has been said that Galileo Galilei performed an experiment in which he simultaneously dropped two dense objects with unequal masses from the Leaning Tower of Pisa. Contrary to to the popular predictions of many other people, the objects hit the ground at the same time (even though one was significantly heavier than the other).

Jump forward a century or so and consider Isaac Newton's second law of motion.

[tex] \vec F = m \vec a [/tex]

Even if the mass [itex] m [/itex] is a variable in this equation, what it is that remains constant when considering objects falling due to gravity? Does [itex] \vec F [/itex] remain constant or does [itex] \vec a [/itex]?

Now it might help to repeat the same consideration, except instead of objects in perfect free fall, apply the considerations to various sized masses on a frictionless incline.

Can you see the relationship between that and an approximation to a pendulum? (Hint: assume small angles)

//=============

// Consideration 2

//=============

Now consider various sized masses attached to a particular, ideal spring. Suppose the spring also has particular compression

Don't forget Newton's second law,

[tex] \vec F = m \vec a [/tex]

In this situation with a particular spring at a particular displacement, what is it that stays constant even if the mass changes? Does [itex] \vec F [/itex] remain constant or does [itex] \vec a [/itex]?

Last edited:

- #3

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A pendulum is an example of a simple harmonic ocillator.

Think about this too:

When you increase the mass of the pendulum the intertia of the pendulum increases the same as the force of gravity on the pendulum. The extra force of gravity is canceled exactly by the increase in inertia. Hence the resulting acceleration is constant but for a larger mass it take more force to achieve. Exactly the extra force provided by the addition mass.

- #4

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Marty1 and Collinsmark thanks alot you guys , that was really helpful! :D

Think about this too:

When you increase the mass of the pendulum the intertia of the pendulum increases the same as the force of gravity on the pendulum. The extra force of gravity is canceled exactly by the increase in inertia. Hence the resulting acceleration is constant but for a larger mass it take more force to achieve. Exactly the extra force provided by the addition mass.

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