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Difference Equation

  1. Jun 18, 2008 #1
  2. jcsd
  3. Jun 18, 2008 #2

    George Jones

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    Rearranged slightly, the equation above it is

    [tex]
    \frac{\partial^2 \phi_\epsilon \left( x \right)}{\partial x} = \frac{2m}{\hbar^2} \left( V_\epsilon \left( x \right) - E \right) \phi_\epsilon \left( x \right).
    [/tex]

    What happens when you integrate both sides of this equation from [itex]x = x_1 - \epsilon[/itex] to [itex]x = x_1 + \epsilon[/itex]?
     
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