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Difference equation

  1. Feb 7, 2009 #1
    Hi guys

    I have this difference equation.

    y(n)-y(n-1)+0.25y(n-2)=x(n)-0.25x(n-1)

    I found the step response of the system from the homogeneous solution and it's

    yh(n)=C1(0.5)n+C2n(0.5)n >>>homogeneous

    h(n)=(0.5n+1)(0.5)n >>> step response

    The 2nd part of the problem is I'm supposed to find the response of the system if x(n)=(0.25)nu(n) is the input and initial conditions =0.

    so my question is how do I find the particular solution ( yp(n))?
    I tried for yp(n)=C(0.25)n,Cn2(0.25)n, but i couldn't find the response.
    I also tried to solve it with convolution but it didn't work.

    So please guys i would really appreciate your help.
    thanks.
     
    Last edited: Feb 7, 2009
  2. jcsd
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