1. The problem statement, all variables and given/known data 1) Find all pairs of natural numbers whose squares differ by 75. 2) Find all pairs of natural numbers whose squares differ by 79. 3) Prove that there can only be 1 pair of numbers with a prime number difference 2. Relevant equations none 3. The attempt at a solution from common sense i can conclude that the answer to question 1 is: 5 and 10. But i need an equation of some sort to get question 2. and im not exactly sure what question 3 is asking.