(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Water is flowing through a horizontal pipe that has a radius of 6 cm gradually narrowing to a

radius of 4 cm. The volume flow rate is 0.008 m3/s. What is the difference in the water pressurebetween the 6 cm radius region and the 4 cm radius region of the pipe?

2. Relevant equations

P + .5pv^2 + pgy = constant

3. The attempt at a solution

y is 0 so that part cancels

p(density) is 1000 kg/m^3 for water

P1 + .5pv1^2 = P2 + .5pv2^2

Not sure where to go from there

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# Homework Help: Differences in Pressure

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