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[tex]y' = 6\frac{y\ln y}{x}[/tex]

After separation and integration, I got

[tex]\ln[\ln y] = 6\ln x + c_1[/tex]

[tex]\Rightarrow \ln y = e^{\ln x^6 + c_1}[/tex]

I am not sure how to get this into an explicit form for y, without it getting nasty. I know that there is usually a trick to make it look cleaner.

Any thoughts?

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# Homework Help: Differential Equation 1

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