Differential Equation Challenge

  • Thread starter josek6
  • Start date
  • #1
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Solve showing full working
(x^2 -1)y' + 2xy = x

You must show full working.
 

Answers and Replies

  • #2
lurflurf
Homework Helper
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No full workings here, were fresh out.
Try to rearrange and find an integrating factor u such that
u(x^2 -1)y' + u(2xy - x)

is and exact differential
 
  • #3
4
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Find the integerating factor "u"
So I have to rewrite the equation in the standard form y' + Py =Q
IF = e ^ ∫P.dx
where P = 2x ???
 
  • #4
4
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Thanks....I solved it my solution is
y(x^2 -1)=(x^2)/2
 
  • #5
lurflurf
Homework Helper
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Good, but you need the arbitrary constant
y(x^2 -1)=(x^2)/2+C
 
  • #6
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I must commend you guys for all the assistance and I will surely recommend you guys to my friends. Thanks again.
 
  • #7
CGZ
2
0
(x^2 - 1 ) y' + 2xy = ((x^2-1)y)' = x;-->
(x^2-1)y = \int{x};-->
(x^2-1)y = 0.5 x^2 + C

y = (0.5 x^2 + C) / ( x^2 - 1 )
 

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