Differential Equation Help

  • Thread starter Sparky_
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  • #1
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Homework Statement


Find the charge on the capacitor in an L-R-C circuit at time t = 0.001

L = 0.05H, R = 2 ohms, C = 0.01F

q(0) = 5
i(0) = 0
E(t) = 0


Homework Equations





The Attempt at a Solution



[tex] L \frac {di(t)}{dt} + R \frac {dq(t)}{dt} + \frac {q}{C} = 0 [/tex]

[tex] \frac {dq^2(t)}{dt^2} + \frac {R} {L} \frac {dq(t)}{dt} + \frac {q}{LC} = 0 [/tex]


[tex] \frac {dq^2(t)}{dt^2} + 40 \frac {dq(t)}{dt} + 2000q = 0 [/tex]

[tex] m^2 = 40m + 2000 = 0 [/tex]

[tex] q(t) = e^{-20t} (c1 * cos(40t) + c2 * sin(40t)) [/tex]

q(0) = 0 yields c1 = 5

[tex] q'(t) = i(t) = -20e^{-20t} (c1 * cos(40t) + c2 * sin(40t) ) + e^{-20t}(-200 sin (40t) + 40*c2*cos(40t))[/tex]


c1 = 5
c2 = 5/2

I get q(0.01) = 4.11 coulombs

The book has q(0.01) = 4.568 coulombs

Can you help resolve my error?

Thanks
-Sparky_
 
Last edited:

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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[tex] q(t) = e^{-20t} (c1 * cos(40t) + c2 * sin(40t)) [/tex]

q(0) = 0 yields c1 = 5
Hi Sparky! :smile:

Isn't c1 = 0? :confused:
 
  • #3
220
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sorry,

my mistake
q(0) = 5

c1 = 5

-Sparky
 
  • #4
Tom Mattson
Staff Emeritus
Science Advisor
Gold Member
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Sparky:

You got the wrong answer because your calculator was in degree mode. Put it in radian mode (like it should be), and you get the book's answer.
 
  • #5
220
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Ahh!!

I was using a calculator I wasn't familar with and didn't check the trig settings.

Thanks so much!
 
  • #6
220
4
Do you agree with my q(t) =

[tex] q(t) = e^{-20t} (5 cos(40t) + \frac{5} {2} sin(40t)) [/tex]

??


There is a second part to this problem -

Find the first time q is equal to 0.

Thanks to Kreizhn I have

[tex] 0 = e^{-20t} (5cos(40t) + \frac{5} {2}sin(40t)) [/tex]

[tex] 0 = (5cos(40t) + \frac{5} {2}sin(40t)) [/tex]

[tex] cos(40t) = -\frac{1} {2}sin(40t)) [/tex]

[tex] 40t = -1.1.07 [/tex]

[tex] t = -0.0276 [/tex]

[tex] 40t = -1.1.07 + pi [/tex]

[tex] 40t = 2.0345 [/tex]

[tex] t = 0.0508 [/tex]

The book gets t = 0.0669.

Suggestions?

Thanks
-Sparky_
 

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