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Find the particular solution of the differential equation [tex]xdy=(x+y-4)dx[/tex] that satisfies the initial condition [tex] y(1)=7 [/tex].

The attempt at a solution

Ok heres my first two steps...

[tex] dy = \frac{(x+y-4)}{x} dx [/tex]

[tex] \frac{dy}{(x+y-4)} = \frac{dx}{x} [/tex]

Now here's where I get messed up. How can I get the x out of the side with the dy? Could someone please explain how to finish this or If I'm headed in the right direction?

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# Homework Help: Differential equation help

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