Differential equation help

  • #1
d²y/ dx² = - h y / j

where h, j are constants. What's y?
 

Answers and Replies

  • #2
This on its own is not actually a question in my assignment but it is a starting point I need to get the problem done.
 
  • #3
gabbagabbahey
Homework Helper
Gold Member
5,002
6
Can you think of a function whose second derivative is proportional to it?
 
  • #4
I know y is an exponential function with a multiplication constant out the front, just not sure what the argument of the exponential is.
 
  • #5
Actually I know it's going to be the sum of two exponentials with different multipliation contants and one will have the negative argument of the other.
 
  • #6
In other words I know it's in the form

y = Aexp(c) + B exp (-c), just not sure what the c is.
 
  • #7
gabbagabbahey
Homework Helper
Gold Member
5,002
6
Since, the derivative is respect to x, why not try [itex]kx[/itex] where [itex]k[/itex] is a constant (it may be complex) for your argument? In fact, the general solution has two terms [itex]y(x)=Ae^{kx}+Be^{-kx}[/itex]. When you plug this into your DE, what do you get?
 
  • #8
and k = sqrt (- h/j)?

so it is a complex argument as I was expecting because a complex exp can be written in terms of sines and cosines, whose 2nd derivative is their own negative.
 
  • #9
gabbagabbahey
Homework Helper
Gold Member
5,002
6
Yes, exactly so you may as well write [itex]y(x)=Csin(\frac{h}{j}x)+Dcos(\frac{h}{j}x)[/itex]
 
  • #10
Thank you, gabbagabbahey.
 
  • #11
125
2
This is a ay''+by'+cy=0 problem which has been discussed to death on every DE book. One should be able to write down the results (when b^2-4ac>0,<0 and = 0) while sleeping.
 

Related Threads on Differential equation help

  • Last Post
Replies
2
Views
927
  • Last Post
Replies
5
Views
924
  • Last Post
Replies
11
Views
2K
  • Last Post
Replies
3
Views
733
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
8
Views
2K
  • Last Post
Replies
4
Views
988
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
2
Views
969
Top